Question

Brand name 2: Tums ran out of time First run Second run Third run Volume HCl used (L, include all sig figs) 0.05 0.05 Molarity of HCI 0.492 0.492 MOLES of HCl used total Volume NaOH used (L, include all sig figs) 0.04869 0.04839 Molarity of NaOH 0.509 0.509 MOLES of NaOH used mount of excess HCl (moles titrated with NaOH) MOLES of HCl neutralized by antacid MOLES of CaCO3 in tablet lass of CaCO3 (g) Mass of CaCO3 based on label on package 500 mg 500 mg difference in mass of CaCO3 in tablet ompared to package information Note: Mass of CaCO3 in the tablet is not the same as the mass of tablet! Calculations:

          Brand name 2: Tums
ran out of time
First run
Second run
Third run
Volume HCl used (L, include all sig figs)
0.05
0.05
Molarity of HCI
0.492
0.492
MOLES of HCl used total
Volume NaOH used (L, include all sig figs) 0.04869 0.04839
Molarity of NaOH
0.509
0.509
MOLES of NaOH used
mount of excess HCl (moles titrated with
NaOH)
MOLES of HCl neutralized by antacid
MOLES of CaCO3 in tablet
lass of CaCO3 (g)
Mass of CaCO3 based on label on package
500 mg
500 mg
difference in mass of CaCO3 in tablet
ompared to package information
Note: Mass of CaCO3 in the tablet is not the same as the mass of tablet!
Calculations:

Show more…

Added by Janice D.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

06/23/2023

Step 1

To calculate the moles of HCl used, we need to use the volume and molarity of HCl. The volume of HCl used is given as 0.05 L. Since the molarity of HCl is not provided, we cannot calculate the moles of HCl used. Show more…

Show all steps

lock

Thanks for your feedback!

Help? The last row is "% difference..." Brand name 2: - TUMS ran out of time Second run Third run First run Volume HCl used (L, include all sig figs) 0.05 L CO2.. 0.492 L Molarity of HCl MOLES of HCl used total Volume NaOH used (L, include all sig figs) 0.04869 L Molarity of NaOH 0.309 M MOLES of NaOH used 0.04839 mol 0.509 mol Amount of excess HCl (moles titrated with NaOH) MOLES of HCl neutralized by antacid MOLES of CaCO3 in tablet Mass of CaCO3 Mass of CaCO3 based on label on package 500 mg difference in mass of CaCO3 in tablet compared to package information Note: Mass of CaCO3 in the tablet is not the same as the mass of tablet! Calculations:

Play audio

Feedback

Powered by NumerAI

Adi S and 84 other subject Chemistry 101 educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later