00:02
Hi there.
00:03
In this question, we have a combustion reaction and it looks like we are trying to use a mole ratio to solve this problem.
00:11
Therefore, what we first need is a balanced chemical equation.
00:15
So we have a combustion reaction where we are combusting or burning hepane, c7h6.
00:24
So it is reacting with oxygen from the air and it's producing carbon dioxide and water vapor.
00:33
All right, so to balance this, we have seven carbon on the left, so we need a seven in front of co2 on the right.
00:40
We have 16 hydrogen on the reactant side, so we need an eight in front of h2o to give us 16 hydrogen.
00:47
Now, adding up our oxygen, we have seven times two plus eight, which is 22 oxygen.
00:55
Therefore, i need an 11 in front of the o2 to complete the balancing of this equation.
01:02
Okay, so we have a balanced chemical equation, and that is very useful because a balanced chemical equation gives us the mole ratio in which reactants react and products are formed.
01:14
And that mole ratio comes from the coefficients in this balanced equation.
01:18
And what they're showing us here is that for every one mole of the c7h16, i know it's a one because when no coefficient is written, it's understood that it's a one.
01:28
So for every one mole of the heptane, we need 11 moles of oxygen, will produce 7 moles of co2 and 8 moles of h2o.
01:43
So this gives us our mole ratios.
01:46
Well, in this question, we are starting with 2 .12 moles of the heptane...