Question

Show the state of the stack and the output as the following equation is converted from infix to postfix using the standard stack algorithm. u+(e/(c+z))+b/s Notes: • The Stack and Output columns show the state of the stack and the output string after the symbol in that row has been processed. • All symbols are only one character so you don't need to include any spaces. • The stack fills from the right, ie, the rightmost item in the stack is the top item. • The last row should contain nothing in the Symbol and Stack columns, that is, it should just contain the final output. • Empty rows will be ignored. The standard algorithm # standard infix to postfix algorithm for each symbol s if s is an operand output s else if it is a left parenthesis push s else if it is a right parenthesis pop to output until corresponding left parenthesis popped else # it is an operator pop all higher or equal precedence operators (than s) to output push s pop all remaining operators to output

          Show the state of the stack and the output as the following equation is converted from infix to postfix using the
standard stack algorithm.
u+(e/(c+z))+b/s
Notes:
• The Stack and Output columns show the state of the stack and the output string after the symbol in that row has
been processed.
• All symbols are only one character so you don't need to include any spaces.
• The stack fills from the right, ie, the rightmost item in the stack is the top item.
• The last row should contain nothing in the Symbol and Stack columns, that is, it should just contain the final output.
• Empty rows will be ignored.
The standard algorithm
# standard infix to postfix algorithm
for each symbol s
if s is an operand
output s
else if it is a left parenthesis
push s
else if it is a right parenthesis
pop to output until corresponding left parenthesis popped
else # it is an operator
pop all higher or equal precedence operators (than s) to output
push s
pop all remaining operators to output

Show the state of the stack and the output as the following equation is converted from infix to postfix using the
standard stack algorithm.
u+(e/(c+z))+b/s
Notes:
• The Stack and Output columns show the state of the stack and the output string after the symbol in that row has
been processed.
• All symbols are only one character so you don't need to include any spaces.
• The stack fills from the right, ie, the rightmost item in the stack is the top item.
• The last row should contain nothing in the Symbol and Stack columns, that is, it should just contain the final output.
• Empty rows will be ignored.
The standard algorithm
# standard infix to postfix algorithm
for each symbol s
if s is an operand
output s
else if it is a left parenthesis
push s
else if it is a right parenthesis
pop to output until corresponding left parenthesis popped
else # it is an operator
pop all higher or equal precedence operators (than s) to output
push s
pop all remaining operators to output

Added by Lisa A.

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