Hi, I can't get the correct draft number from following question. I get 0.5195m. Weight of bouy + weight of mooring lines = bouyancy of bouy... Am I wrong? A CALM buoy is moored in 30m water depth using a 6 line configuration. The CALM buoy is cylindrical with a diameter of 5m and mass 5 tonnes. Mooring chain of submerged weight 300 N/m is used throughout. The chain attachment points are on the outer edge of the CALM buoy and at its base. The tension force is measured at the attachments and is 15kN in each chain. a) What is the draft (i.e. distance from the base to the waterline) of the CALM buoy in calm conditions? (answer = 0.6635m).
Added by Liam K.
Step 1
First, we need to find the volume of the submerged part of the buoy. To do this, we'll use the buoyancy formula: Buoyancy = Weight of buoy + Weight of mooring lines Show more…
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