Question

Simulate Tools Window Help K Lp Ls 1 D2 Vout V1 +Lp Ls D1 IN4148 D3 0.0529 0.205m C1 SINE(0 325 50) Rser=0.0001 D4 IN914 1N914 C 1N4148 RL R .tran 50ms

          Simulate Tools Window Help
K Lp Ls 1
D2
Vout
V1
+Lp Ls D1
IN4148
D3
0.0529
0.205m
C1
SINE(0 325 50)
Rser=0.0001
D4 IN914
1N914
C
1N4148
RL
R
.tran 50ms

Added by Becky P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

Step 1

We know that the maximum DC current at the load is 400mA. So, we can choose a value for RL that will allow this current to flow. Using Ohm's Law (V = I * R), we can rearrange the equation to solve for RL: RL = Vout / I RL = 12V / 0.4A RL = 30Ω So, the value of Show more…

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Thanks for your feedback!

Hi, this is half of my linear DC power supply circuit design. For a maximum DC output Vout = 12V and maximum DC current of 400mA at the load RL, what can the values of capacitance C1 and RL be? Please provide necessary explanations as I am required to write a report of my design. And I will rate. KLpLs1 D2 V1 Vout Lp Ls D1 1N4148 D3 0.0529 SINE(033550) 0.205m 1N914 Rser = 0.0001 D4 180914 C1 RL R 1N4148 C .tran 50ms