Hlorine dioxide clo2 which is produced by the reaction below...

hlorine dioxide (ClO2), which is produced by the reaction below, has been tested as a disinfectant for municipal water treatment. 2 NaClO2(aq) + Cl2(g) → 2 ClO2(g) + 2 NaCl(aq) (a) Using data from the Standard Reduction Potentials table, calculate ℰ°, ΔG°, and K at 25°C for the production of ClO2. ℰ° ΔG° K (b) One of the concerns in using ClO2 as a disinfectant is that the carcinogenic chlorate ion (ClO3− ) might be a by-product. It can be formed from the following reaction. ClO2(g) → ClO3−(aq) + Cl−(aq) Balance the equation for the decomposition of ClO2. (Use the lowest possible coefficients. Include states-of-matter at 25°C and 1 atm in your answer.)

Transcript

00:01 Hello guys, so in this question we have been given this equation that says 2 moles of na, clo2 and reacted with cl2 will give us 2 moles of clo 2 plus 1 mole of nacl.

00:23 So this is the equation given and we have to find e0 cell, delta g0 cell and k value of this reaction.

00:34 And we have to use the standard reduction potential tables for all this.

00:38 And the temperature also given is that is 25 degrees celsius so t is equal to 25 degrees celsius now let's firstly write the anode and cathode reactions so anode reaction is cl o2 minus an aquis form will give us cl o2 and one electron so this is the oxidation happening so our e knot oxidation will be equal to minus of 0 .954 volt.

01:16 Now next is cathode.

01:19 The cathode reaction will become pl 2 when 2 electrons add in in this it will give us 2 moles of the 0 minus.

01:28 This is the reduction happening and the e0 reduction is equal to 1 .36 volt now electron transfer is 2 so our n will become 2.

01:46 Now e not cell will be equal to e0 cell is equal to a knot of oxidation plus e not of production.

01:59 So now i'm going to put the values, it will be equal to minus of 0 .954 plus 1 .36.

02:06 It will be equal to the answer that is a0 cell 0 .406 volt.

02:14 So this is the answer for the first part of the question.

02:17 Next we have to find is delta g0.

02:20 So the formula for delta g -not is minus of n f e -not cell.

02:31 So here we have all the values.

02:35 N is equal to minus 2 as calculated above.

02:37 F is faradies constant that is 96500 and e -0 cell that which is calculated is 0 .406...

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