H2O in a closed-piston cylinder undergoes an internally...

Name: H2O in a closed-piston cylinder undergoes an internally reversible, isothermal compression process from 120 °C and 100 kPa until its quality reaches 50%. The initial volume of the cylinder is 1 m³. Find the heat and work transfer (kJ) for the process, and draw the process on a T-s diagram.
Uploaded: 2023-07-16T23:28:50-08:00
Duration: 4 min 51 s
Channel: Adi S
Description: H2O in a closed-piston cylinder undergoes an internally reversible, isothermal compression process from 120 °C and 100 kPa until its quality reaches 50%. The initial volume of the cylinder is 1 m³. Find the heat and work transfer (kJ) for the process, and draw the process on a T-s diagram.

H2O in a closed-piston cylinder undergoes an internally reversible, isothermal compression process from 120 °C and 100 kPa until its quality reaches 50%. The initial volume of the cylinder is 1 m³. Find the heat and work transfer (kJ) for the process, and draw the process on a T-s diagram.

Transcript

00:01 Now in this question we have to find the heat and the work transfer.

00:05 Now for that we have the given value which is p1 is equals to 100 kpa.

00:11 Temperature is given as t1 which is 120 degree celsius and we have volume of the cylinder is 1 m3.

00:26 Sigma 1 is equals to 1 .79 m2 per kg.

00:32 Because the process is isothermal then the value for t2 here it will be equals to t1 which is equals to 120 degree c.

00:43 The value for x2 is equals to 0 .5.

00:49 Now because we have t2 as 120 degree celsius so uf will be equals to 504 ks upon kg.

01:02 Value for ug is equals to 2530 kg upon ks.

01:11 The value for vf is equals to 0 .00106 m3 per kg and the value for vg is equals to 0 .891 m3 per kg.

01:30 Thus from here we can write that mass of h2o that is mass of water is equals to v1 upon sigma 1 which will be giving us 1 upon 1 .79 that is ultimately equals to 0 .558 kg.

01:51 Thus finding the specific volume we will get the specific volume that is v2 is equals to vf plus x2 multiplied by vg minus vf.

02:03 Putting the value and solving it we get 0 .00106 plus 0 .5 multiplied by 0 .851 minus 0 .00106.

02:20 So solving it we get v2 is equals to 0 .446 m3 per kg.

02:30 This is the value for v2.

02:32 Now writing down the specific internal energy that will be given by u2 it will be equals to uf plus x2 multiplied by ug minus uf.

02:46 Thus it will be 504 plus 0 .5 multiplied by 2530 minus 504...

Question

H2O in a closed-piston cylinder undergoes an internally reversible, isothermal compression process from 120 °C and 100 kPa until its quality reaches 50%. The initial volume of the cylinder is 1 m³. Find the heat and work transfer (kJ) for the process, and draw the process on a T-s diagram.

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