Assume the population proportion is to be estimated from the sample described. Find the approximate margin of error and the 95% confidence interval for the population proportion. Sample size = 1,093, sample proportion = 0.248 The margin of error is (Round to four decimal places as needed.)
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248 Sample size, n = 1093 Standard error = sqrt(p*(1-p)/n) Standard error = sqrt(0.248*(1-0.248)/1093) Standard error = sqrt(0.186304/1093) Standard error = sqrt(0.0001705) Standard error ≈ 0.01306 Show more…
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