The energy diagrams shown to the right correspond to the...

The energy diagrams shown to the right correspond to the reactions A + B ? AB and D + E ? DE. Both processes have the same activa- tion energy $E_a$. ? E P A + B E ? E p E DE AB D + E Reaction Path Reaction Path Reaction Rate Homework • Unanswered • Due Mar 13th, 11:30 AM If we assume that T, P, and the initial concentrations of all of the reactants in these two processes are the same. Which of these reactions would you expect to be faster? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a A + B b D + E c Both would have a similar rate d More information is needed to decide

Transcript

00:01 So let's look at the reaction.

00:02 So a plus b will give us c.

00:04 This is the reaction.

00:06 Now rate can be calculated that equals to k, which is the rate constant and a to the power of let's say m and b to the power of concentration of v to the power of n.

00:17 So here a is taken in large axis.

00:20 So a isn't going to be affected during the reaction.

00:23 So this will be taken as constant.

00:26 So now we can say that rate equals to so, k into b to the power of n where a is constant or we can say that here k bar.

00:42 So k bar will be equals to k u to the power of m if we substitute this and this.

00:49 So if rate is substituted in that.

00:52 So we can say that let the order of the reaction with respect to b is zero.

00:58 So, order of reaction with respect to b will be equals to 0.

01:10 So, now we can say that rate will be equals to here k bar.

01:17 So we can write the rate as like this in the differential form, that is minus d to the power of 2 into the concentration of, and t t that equals to k dash now we can say that by integrating we will get b 0 b minus concentration of b will be equals to k bar t so this will be the first equation let's suppose say so while if we calculate this or can be written as if we simplification this concentration of b will be equals to concentration of b will be equals to concentration of b0 minus k dash t so this we can write so now if we see uh which assembles between concentration of b and k there is a straight line and negative minus k dash and y intercept of b not so we can say that a conclusion that order of the reaction with respect to b will be equals to 0 that is n equals to 0 so this will be the order of the reaction with respect to b now as per the given values we can calculate the concentration of a is given that is a 1 equals to 0 .075m so slope is given slope will be equal to minus 1 .25 into 10 to the power of minus 3 m per second.

03:02 So now here slope is equal to as we discussed it will be equals to minus of k bar...

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