Question

The current through the circuit is calculated as, \(i(t) = \frac{v(t)}{Z}\) \(= \frac{15(\cos 2t)}{80 + j0.480 - j100}\) \(= \frac{15(\cos 2t)}{127.688\cos (-51.205)}\) \(= 117.473\cos (2t + 51.205^\circ) \text{ mA}\) Explanation: When the voltage across the inductor and the capacitor are equal, the RLC circuit is said to be in resonance.

          The current through the circuit is calculated as,
\(i(t) = \frac{v(t)}{Z}\)
\(= \frac{15(\cos 2t)}{80 + j0.480 - j100}\)
\(= \frac{15(\cos 2t)}{127.688\cos (-51.205)}\)
\(= 117.473\cos (2t + 51.205^\circ) \text{ mA}\)
Explanation:
When the voltage across the inductor and the capacitor are equal, the
RLC circuit is said to be in resonance.

The current through the circuit is calculated as,
i(t) = (v(t))/(Z)
= (15(cos 2t))/(80 + j0.480 - j100)
= (15(cos 2t))/(127.688cos (-51.205))
= 117.473cos (2t + 51.205^∘) mA
Explanation:
When the voltage across the inductor and the capacitor are equal, the
RLC circuit is said to be in resonance.

Added by Shelby M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Khoobchandra Agrawal

09/03/2020

Step 1

Step 1: The given expression for the current through the circuit includes complex numbers in the form of j values. Show more…

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Thanks for your feedback!

How are these j values being transformed into cos/sin? Could I please have an explanation? Thank you. The current through the circuit is calculated as: it = vt Z 15(cos2t) 80 + j0.480 - j100 15cos2t 127.688cos(51.205) 117.473cos2t + 51.205mA Explanation: When the voltage across the inductor and the capacitor are equal, the RLC circuit is said to be in resonance.