00:01
Here we have a question about the theoretical yield of a hydrazine reaction.
00:04
The chemical formula is 2 n -a -o -h - sodium hydroxide, plus 2 nh3, ammonia, plus cl2, chlorine gas, yields hydrazine n2h4, 2 sodium chloride, nacl, plus 2h -2o, or water.
00:29
Now, we want to determine the theoretical yield of hydrazine, given, then we are reacting one kilogram of chlorine gas with excess sodium hydroxide and ammonia.
00:43
So we will do this first by taking our 1 .00 kilograms of chlorine gas, converting that into grams of chlorine.
00:58
With the conversion there are 1 ,000 grams in every 1 kilogram.
01:03
Then we will multiply by the molar mass of chlorine, which is 70 .9 grams of diatonic chlorine per mole.
01:13
Then we'll use the mole ratio given by the stoichiometry of the chemical reaction, where for every one mole of chlorine consumed, we produce one mole of hydrazine...