How do you find the real and imaginary components of z = z1z2 if z1 = 1 + i and z2 = e^(2 + (iπ/6))? Please explain how you got there.
Added by Amparo R.
Step 1
To find the polar form of z1, we can use the formula r = √(a^2 + b^2) and θ = arctan(b/a), where a and b are the real and imaginary components of z1. For z1 = 1 + i, we have a = 1 and b = 1. Therefore, r = √(1^2 + 1^2) = √2 and θ = arctan(1/1) = π/4. So, z1 in Show more…
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