00:01
In this problem, we have been given that there is a string.
00:05
So let's say l is the length of the string and it's connected at the two ends.
00:11
So it's fixed at the two end points.
00:14
And here we are required to get the factors on which the frequency of vibration of the string will depend.
00:23
Considering the tension in the string as t here and mu as the linear mass density, we see that the frequency of vibration, that's the natural frequency.
00:38
This is the first mode of vibration.
00:40
And in this case, the two nodes are formed at the end points and the distance between the two nodes, we know it is lambda over two.
00:49
So the length is lambda over two.
00:51
And from here we get lambda as 2l.
00:54
And lambda, we know it is the wavelength...