00:01
In this question we have to show the complete mechanism for the clazine condensation.
00:22
Moving on to the solution, first we have to tell that what is clazine condensation.
00:34
So, the esters having an alpha hydrogen undergo condensation in the presence of strong base like n -a -o -c -h -2 -ch -3 to form beta keto -ester.
01:12
So this reaction is called the clazine condensation.
01:17
Now we have to show the reaction.
01:24
So the reaction is like this, ch3, so it is bonded with the oxygen and to another carbon and methyl group here.
01:49
So on this oxygen there are two lone pair of electrons and here there is double bond.
01:57
Double bonded oxygen is attached with two lone pairs of electron.
02:06
So it is treated with number 1 o minus ch2, ch3 or ch3, or ch3, ch2, oh, and number 2 is with hydronium ion.
02:36
So it forms this structure.
02:53
So here the double bonded oxygen with two lone pair of electrons and here another double bonded oxygen with two lone pair of electrons.
03:08
So this is called the beta keto ester plus this has been formed with this oxygen having two lone pairs of electron and an hydrogen atom is attached so this is oh h group and here a methyl group is attached so this is the reaction now we have to show the curved arrow mechanism for this reaction so first we we will do step wise.
04:08
So step first.
04:12
Now the strong base ethoxide here we will draw the structure of ethoxide.
04:26
So it has three lone pair of electrons and a negative charge.
04:33
So it abstracts the alpha hydrogen from the ester.
04:38
So we will draw the structure of the ester.
04:41
Here it is the structure of the ester.
04:56
Here c .h2, c .h .3.
05:02
And here, double bonded oxygen with two lone pairs.
05:09
And on this group, three hydrogen atoms are present.
05:18
So we have elaborated the structure to make it clear.
05:22
So this ethoxide, it abstracts the alpha hydrogen from the ester and this the electron will be shifted here.
05:37
So this is the first step...