00:01
Hello, here we have to solve the following problem.
00:07
So we have to write down the standardization reaction between potassium permanganate and iron 2 plus and then between potassium margonate and oxalidate in acedic media.
00:20
So let's start with the first reaction.
00:23
Here, potassium permanganate reacts with iron 2 plus and it forms.
00:35
Iron 3 plus manganis 2 plus and water and of course potassium let's balance half reactions on the one hand mno4 minus becomes mn2 plus and water so we have to add four water molecules to balance this half reaction to balance oxygen and now we have to eight protons and five elections to the left to balance for the charge.
01:20
Now let's write down the reaction for oxidation of iron 2 plus to iron 3 plus and that's a simple 1 electron oxidation.
01:29
So overall that's a 5 election process and that's why the first reaction has to be multiplied by 1 and second by 5.
01:37
So that's why we place a coefficient of 5 before irons and coefficient before manganic species will be 1.
01:45
And so is the coefficient before potassium plus now let's check for the charge let's not forget to add four before water and here we also have to add eight protons so let's check for the charge the charge on the left is 18 plus charging the right is also 18 plus and everything else is balanced so now let's move on to the second question here we have to balance the reaction between potassium permanganate and oxalic acid let's do this so it forms so it will be forming co2 manganase 2 plus potassium plus and now we have to balance water and hydrogen.
03:38
Let's do this.
03:39
So let's again start with the half reaction from mnof minus...