How many calories of heat are released when 200 g of steam at 120°C is changed to ice at -12°C?
Added by Richard W.
Step 1
Step 1: Calculate the change in temperature (ΔT): Given T1 = 120°C and T2 = -12°C ΔT = T1 - T2 ΔT = 120°C - (-12°C) ΔT = 132°C Show more…
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