00:01
So to solve for this, we need the chemical formulas of each compound.
00:11
Okay, so for ethane, ethane is c2h6.
00:16
So that means if we have one molecule of c2h6, if we convert this to number of moles, we'll divide it by a bogratus constant and stand to the 23 molecules.
00:30
This is molecules.
00:32
For every mole of c2h6.
00:36
And then we will write the molar ratio of carbon to c2h6.
00:44
You can see we have for every mole of c2h6, we have two moles of carbon, right? and then we are looking for the number of atoms of carbon.
00:55
So that means, again, we'll multiply this by avogadro's number, which is now in atoms.
01:03
And this is for every more carbon.
01:07
So as you can see, we can cancel some numbers...