00:01
Hi, so to solve for this, let's write first the electron configuration of arsenic.
00:09
Let's write the orbitals.
00:13
We have 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f, and we're solving for the number of electrons in the fourth shell of arsenic.
00:28
So we'll stop here and remember that as orbital can hold up to 2 electrons, p can hold up to 6, d can hold up to 10, and this can hold up to 14.
00:39
So next we will get the number of electrons for arsenic from the predict table.
00:51
The atomic number of arsenic is 33 and this is a neutral atom, so that means it is also equivalent to the number of electrons in arsenic.
01:01
So we have 33 electrons.
01:04
Let me just rewrite this one.
01:07
Let's write it here.
01:10
Arsenic has 33 electrons.
01:15
So first shell 1s2, this can hold up to 2 electrons, so this will be field.
01:21
And then we'll have 2s2, 2p6, since the p orbital can hold up to 6, and then 3s2, 3p6, and this can hold up to 10.
01:32
So let's calculate the number of electrons now...
