How many g of cobalt(II) chloride ($M_m$ = 129.84 g/mol) are in 0.375 L of a 1.95 M solution? 178 g 94.9 g 66.6 g 253 g 0.192 g
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We can use the formula Molarity (M) = moles of solute / liters of solution. Rearranging the formula to solve for moles of solute, we get: moles of solute = Molarity (M) x liters of solution moles of solute = 1.95 M x 0.375 L moles of solute = 0.73125 moles Show more…
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