00:01
Hello students, welcome here in this question.
00:02
There are three parts in this question.
00:04
So first part they are given here how many moles of how many grams of fe required to produce 1 .75 moles of fe cl3.
00:20
So this is a question.
00:22
So we'll see here the reaction is fe plus cl2, gist, 2 is a reaction.
00:29
So here if you take f .e.
00:34
Cl3.
00:35
So if this one is 3 moles, this is 2 moles and this one is 2 moles.
00:41
If 1 .75 fe we want 2 moles of fe reacting to give 2 moles of fe cl3.
00:51
So 1 .75 moles if we want to produce how many moles of this one is required, same amount of fe is required.
01:00
So, 1 .75 moles of fe required to produce 1 .5 moles of efficiency.
01:13
But we have to calculate here mass.
01:17
So mass of fe required is equal to number of moles multiplied by molar mass.
01:30
So molar mass for mass, fe is 56 grams approximately.
01:35
Approximately so that one is equal to 98 grams of f .e is required to produce 1 .75 moles of fe.
01:46
Okay, so this is the first question and now the second question is they are given same reaction, but here how many moles of chlorine is required? so chlorine we want.
01:58
So three moles of chlorine is reacting to give two moles of f .e.
02:05
F .cl2, but f .e...