How many grams of Aluminum Oxide are produced when 3.64 g of Aluminum reacts with an excess of Oxygen? 4Al + 3O2 → 2Al2O3 _ grams of Al2O3 (round to 3 sig figs)
Added by Sharon B.
Step 1
Step 1: Calculate the molar mass of Al2O3 Molar mass of Al = 27 g/mol Molar mass of O = 16 g/mol Molar mass of Al2O3 = 2(27) + 3(16) = 54 + 48 = 102 g/mol Show more…
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Aluminum reacts with oxygen to give aluminum oxide. $$ 4 \mathrm{Al}(\mathrm{s})+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{Al}_{2} \mathrm{O}_{3}(\mathrm{~s}) $$ If you have $6.0 \mathrm{~mol} \mathrm{Al}$, how many moles and how many grams of $\mathrm{O}_{2}$ are needed for complete reaction? What mass of $\mathrm{Al}_{2} \mathrm{O}_{3}$, in grams, is produced?
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