How many grams of copper are deposited on the cathode of an electrolytic cell if an electric current of 2.00 A is passed through a solution of CuSO4 for a period of 19.0 min?
Added by Judith C.
Step 1
First, we need to find the total charge passed through the cell. We can do this by multiplying the current (2.00 A) by the time (19.0 min) and converting the time to seconds. Total charge (Q) = Current (I) × Time (t) Q = 2.00 A × (19.0 min × 60 s/min) Q = 2.00 A Show more…
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