How many grams of copper metal can be deposited from CuĀ²āŗ(aq) when a current of 2.50 A is run for 1.40 h? (F = 96,500 C/mol)
Added by Lorena S.
Step 1
First, we need to find the total charge (in Coulombs) passed through the solution. We can do this by multiplying the current (in Amperes) by the time (in seconds): Current (I) = 2.50 A Time (t) = 1.40 h = 1.40 * 3600 s = 5040 s Total charge (Q) = I * t = 2.50 A Show moreā¦
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