00:01
In this question, we are assigned to the task to calculate the mass of lead product will be formed.
00:12
It is given that we have 17 .0 gram of potassium iodide, that is ki, and 25 .0 .03 haledwise, that is lead nitrate.
00:30
The balanced chemical equation is 2k .i plus ppno3, haltwise, gives out pbi2 plus 2kno3.
00:47
Now, the molar mass for ki is 166 .003 gram per mole, and for lead nitrate, it is 3331 gram per mole, and for lead nitrate it is 331 gram per mole.
01:00
Per mole.
01:01
We will calculate the malls of ki, which is equals to mass divided by molar mass, that is 17 divided by 16603, which comes out to be 0 .10.
01:19
Similarly, the number of malls for pb.
01:24
N03, whole twice, is equal to 25 divided by 331.
01:35
3...