How many grams of NaCl are contained in 350. mL of a 0.115 M solution of sodium chloride? 4.70 g 40.3 g 2.35 g none of these 6.7 g
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Given: Molarity (M) = 0.115 Volume (V) = 350 mL = 0.350 L Number of moles = Molarity x Volume Number of moles = 0.115 x 0.350 Number of moles = 0.04025 mol Show more…
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