How many grams of NaOH are needed to completely react with 65.2 grams of HBr? HBr + NaOH --> NaBr + H$_2$O
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Molar mass of HBr = 1.008 g/mol + 79.904 g/mol = 80.912 g/mol Molar mass of NaOH = 22.990 g/mol + 15.999 g/mol + 1.008 g/mol = 40.00 g/mol Show more…
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