00:01
Hello students, let's begin with this question.
00:02
So, in the first part this data is provided and we have to find out the mass of the k2so4.
00:08
So, firstly here volume and density is given.
00:11
So, by using the relation that density is equals to mass divided by the volume, we can find out the mass of the solution.
00:21
So, here the mass of the solution is equals to 623 ml multiplied by 1 .23 gram per ml.
00:32
So, here we get the mass which is equals to 766 .29 gram.
00:37
So, now here the mass percent is equals to the mass of the solute upon the mass of the solution and this is multiplied by the 100 as we are calculating the percentage here.
00:55
So, here mass percentage is given which is equals to 22 .5 percent is equals to the mass of the k2so4 upon mass of solution is 766 .29 gram multiplied by 100.
01:08
So, now when we solve this we get here that we get here the mass of the k2so4 is equals to 163 gram.
01:23
Now, next here the volume and the molarity of hbr is given and here we have to find out the mass of the hbr.
01:30
So, firstly we have to find out the moles here.
01:32
So, the moles of the hbr is equals to molarity multiplied by the volume in liter.
01:42
So, now substituting the values over here.
01:45
So, here molarity value is equals to 11 .0 molar or this can be written as moles per liter.
01:51
Volume is 100 ml divided by 1000 to convert this into liter.
01:55
So, here the moles comes to be 1 .1 moles.
01:57
Now, we have the moles from moles we can find out the mass.
02:01
So, the mass of the hbr is equals to its moles multiplied by the molar mass.
02:07
So, now substituting the values over here.
02:11
So, here the these moles is equals to 1 .1 moles and here the molar mass is this molar mass is equals to here comes the 80 .911 gram per mole.
02:28
So, when we solve this we get here the mass of the hbr which is equals to 89 .0 gram...