How many grams of water can be heated from 20.0 °C to 65°C using 13500.0 Joules? The specific heat of water is 4.184 J/g°C. q = m * Cp * ΔT 71.7g 52.5g 0.01g 98.3g
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0 J - Specific heat of water (Cp) = 4.184 J/g°C - Initial temperature (T1) = 20.0°C - Final temperature (T2) = 65.0°C Show more…
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