How many grams of water form when 2.74 L of O2 gas at STP completely reacts with H2? (molar mass H2O = 18.02 g/mol) 2H2(g) + O2(g) → 2H2O(g) 4.41 g H2O 2.00 g H2O 0.998 g H2O 0.04988 g H2O
Added by David T.
Step 1
First, we need to find the moles of O2 gas. At STP, 1 mole of any gas occupies 22.4 L. So, we can find the moles of O2 by dividing the volume by 22.4 L/mol. Moles of O2 = 2.74 L / 22.4 L/mol = 0.12232 mol Show more…
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