\[
\text{Molar mass of } (\text{NH}_4)_2\text{CO}_3 = 2 \times \text{Molar mass of NH}_4 + \text{Molar mass of CO}_3
\]
\[
\text{Molar mass of NH}_4 = 14.01 \, (\text{N}) + 4 \times 1.01 \, (\text{H}) = 18.05 \, \text{g/mol}
\]
\[
\text{Molar mass of CO}_3 =
Show more…