00:03
Hi there.
00:03
In this question, we want to know how many lone pairs of electrons are on the iodine in if4 with a positive charge.
00:16
So in this polyatomic ion.
00:19
All right.
00:19
So iodine is a halogen.
00:21
We know that it has seven valence electrons.
00:24
Flooring is also a halogen.
00:26
So each fluorine has seven valence electrons.
00:30
And there are, of course, four of those.
00:33
And then that plus sign means that we have long.
00:35
Lost one electron.
00:39
All right, so if we wanted to determine the total number of electrons here, four times seven is 28, plus seven is 35 minus 1 equals 34.
00:55
All right, so we need 34 electrons in this structure.
00:59
So we're going to put iodine in the center and fluorine just around its four sides, one fluorine on each side.
01:11
These fluorines we know have seven valence electrons of their own.
01:17
And flooring only forms a single bond.
01:25
So each flooring is going to share one electron with iodine in forming the covalent bond that connects them...