00:01
Hi there.
00:02
In this question, we have an acid -based neutralization.
00:05
So the first thing we want to write is a balanced equation.
00:09
So we have h -n -o -3 reacting with calcium hydroxide, which is cao -h -2.
00:22
So we're going to form a salt and water.
00:25
And really, it's just a double replacement.
00:27
So we get calcium with nitrate.
00:31
We need two nitrates, since she only has a one negative charge while calcium has a two positive charge.
00:38
And we get water.
00:40
It's our other product.
00:42
All right.
00:43
To balance this, we need two in front of hno3 to give us two nitrates on both sides.
00:50
And then we notice that we need a two in front of h2o, since we have four hydrogens and two extra oxygens that are not part of the nitrate on each side.
01:01
All right.
01:02
So this is now balanced.
01:04
And we know that we have 2 .00 molar hn .03.
01:11
And we are trying to figure out the volume that is needed to react completely with this one molar solution of calcium hydroxide, of which we use 2 .50 milliliters.
01:31
Okay, so this is a stoichiometry problem.
01:34
We're going to start with our volume of calcium hydroxide that we use.
01:39
Remember, molarity means moles per liter.
01:42
So another way to write this molarity here.
01:45
Here is that 1 .00 moles of caoh2 is equal to one liter of the solution.
01:59
Okay, and the same is true for the hno3, the nitric acid.
02:03
Two moles of that for every liter.
02:07
Okay, so let's get started.
02:08
We have 2 .50 milliliters of the calcium hydroxide solution.
02:18
And i know that molarity is per a liter.
02:21
So the first thing i want to do is convert this to liters.
02:24
There are 1 ,000 milliliters of solution in every liter of solution.
02:32
Now i can use the molarity of calcium hydroxide.
02:36
In one liter of solution, we have 1 .00 moles of the caoh2...