00:01
Hi, so to solve for this we will calculate first the number of moles of iodide ion.
00:08
If we have 0 .200 and this is moles of ki per liter and multiply the volume we have 45 ml and convert them out to liters.
00:20
1000 ml is one liter and then convert moles of potassium iodide ki to moles of iodide.
00:28
So for every one mole of ki we have one mole of iodide and ion and cancel some units now, moles of liters, moles of ki and this will be 9 times 10 to the negative 3 moles of iodide and ion.
00:48
Now for the number of moles of ozone we have 9 times 10 to the negative 3 moles of iodide and ion.
00:59
Based on the given balance equation for every two moles of iodide and ion reacted it will require one mole of ozone o3.
01:09
So now we could cancel moles of iodide and ion and we'll have 4 .5 times 10 to the negative 3 this is moles of ozone.
01:19
Now we will solve for volume using the ideal gas equation pv is equivalent to nrt.
01:26
Rearranging this to solve for volume we'll have nrt over the pressure and plug in the information that we have.
01:32
We have 4 .5 times 10 to the negative 3 moles...