How many moles of ammonia (NH3) are produced by the reaction of 42.85 g of magnesium nitride with excess water? Mg3N2 + 3H2O ? 2NH3 + 3MgO
Added by Samuel M.
Step 1
The molar mass of magnesium (Mg) is 24.31 g/mol, and the molar mass of nitrogen (N) is 14.01 g/mol. So, the molar mass of Mg3N2 is: Mg3N2 = 3 * 24.31 + 2 * 14.01 = 72.93 + 28.02 = 100.95 g/mol Now, we can find the moles of Mg3N2 in 42.85 g: moles of Mg3N2 = Show more…
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