00:01
Hello everyone let's solve this question in this question there are few parts in the first part a reaction is given to fe plus 3 cl2 gives to fecl 3 and it is given that 2 .3 grams of solid fe reacts with 3 .3 grams of chlorine gas to produce fecl 3.
00:24
We have to find out here limiting reactant and we have to find out the amount of f .e.
00:35
Cl3 produced.
00:37
So, let's get started for the part.
00:40
Here we can use the stoichiometry, so by stoichiometry of the reaction, we can say that two moles of fe combines with 3 moles of cl2 gas.
00:55
So if we have suppose 2 .3 moles of of fe, this is not grams, i am sorry, these are the moles given in the question.
01:08
So if we have 2 .3 moles of fe, how many moles of col2 will be required? so that is 2 .3 multiplied by 3 divided by 2, that is 3 .45 moles of chlorine gas are required.
01:27
And we have less amount of moles, therefore we can say that chlorine, is limiting reactant.
01:38
This is the answer to the first part of this question.
01:44
And from the limiting reactant now we can compare and calculate the amount of product, that is three moles of cl2 combines with two moles of fecl3.
01:57
This is by stoichiometry, stoichiometry of the reaction.
02:06
So, if we have 3 .3.
02:09
Moles of cl2 how many moles of fecl 3 will be produced so that is 3 .3 multiplied by 2 divided by 3 that will give us 2 .2 moles of fecl 3 are produced so option 4 is correct here now let's move to the second part of the question that is b part and it says that the reaction 2k plus br2 gives 2k brr.
02:49
Here we have 1 .5 moles of k reacting with how many moles of bromine we have to find out...