How many moles of lithium hydroxide would be required to produce 46.5 g of Li₂CO₃ in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)
Added by Tammy J.
Step 1
The molar mass of Li is approximately 6.94 g/mol, the molar mass of C is approximately 12.01 g/mol, and the molar mass of O is approximately 16.00 g/mol. Therefore, the molar mass of Li₂CO₃ is (2*6.94) + 12.01 + (3*16.00) = 73.89 g/mol. Show more…
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