00:01
Hi, so to solve for this, we need to write first the balance equation for this reaction.
00:06
We have mg3n2 reacting with h2o to form magnesium oxide and ammonia nh3.
00:18
So we have to balance this first, we have to write 3 in here, 2, and that means we have to write 3 here.
00:27
This is the balance equation for this reaction.
00:30
Now we need to determine the limiting reactant first.
00:35
Convert the given mass of reactants to moles.
00:37
We'll start with mg3n2.
00:39
We have 1 .82 grams of this compound.
00:42
Convert to moles by dividing the molar mass of this compound, 100 .93 grams, and we have here moles, so that means we can cancel grams here, and we'll get 0 .0180.
00:56
This is moles of mg3n2.
01:00
And then for water, we have 17 .73 grams divided by the molar mass of water, 18 .02 grams.
01:09
We have here moles, so that means we could cancel grams, and we'll get 0 .984.
01:18
This is moles of water.
01:21
And then we will solve for the mole ratio.
01:24
Mole ratio is the number of moles of the reactant divided by the coefficient of that reactant from the balance equation.
01:31
So for mg3n2, magnesium nitride, we have 0 .0180 moles...