00:01
Hello students, so this video has four parts.
00:04
In the first part, we have the reaction 4kno3 dissociates to give 2k2o plus 2n2 plus 5o2.
00:15
Now, we have 58 .6 g of kno3 and we have to find the number of moles of oxygen produced.
00:22
So, from this we can say that 4 moles of kno3 is equivalent to 5 moles of oxygen.
00:32
So, now we can convert this to moles as well that is 58 .6 by 101 .11 that is the molecular mass of kno3 that is equals to 0 .5796.
00:44
So, we can say that 0 .5796 moles of kno3 is equivalent to 5 by 4 into 0 .5796 moles of oxygen that is equals to 0 .724 moles of oxygen which is option number d.
01:07
Let's move on to the next part.
01:08
So, in the next part, we have nitrogen reacting with 3 hydrogen to produce 2 ammonia and we have 14 .01 g of nitrogen and 3 .02 g of hydrogen.
01:21
So, we have to find the amount of ammonia produced.
01:23
So, now we will calculate the number of moles.
01:26
So, number of moles is 14 .01 by 28 that is 0 .5 and this is 3 .02 by 1 that is approximately 3.
01:35
So, we can see here that 1 mole reacts with 3 moles but we do we have 3 moles but we don't have 1 mole.
01:42
So, that means nitrogen is the limiting reagent...