Question

How many moles of oxygen gas are contained in a diver's tank of volume 12.0L and pressure 3,000psi when the temperature is 15.0°C? $PV = nRT$ $R = \frac{0.0821 Latm}{molK}$ $1 atm = 14.7 psi$ 15.2mol 42.0mol 104mol 0.00966mol

          How many moles of oxygen gas are contained in a diver's tank of volume 12.0L and pressure 3,000psi when the temperature is 15.0°C?
$PV = nRT$
$R = \frac{0.0821 Latm}{molK}$
$1 atm = 14.7 psi$
15.2mol
42.0mol
104mol
0.00966mol

How many moles of oxygen gas are contained in a diver's tank of volume 12.0L and pressure 3,000psi when the temperature is 15.0°C?
PV = nRT
R = (0.0821 Latm)/(molK)
1 atm = 14.7 psi
15.2mol
42.0mol
104mol
0.00966mol

Added by Ashley A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sima Sarker

08/28/2022

Step 1

Using the conversion factor 1 atm = 14.7 psi, we can convert the pressure from psi to atm: 3000 psi * (1 atm / 14.7 psi) = 204.08 atm Show more…

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How many moles of oxygen gas are contained in a diver's tank of volume 12.0L and pressure 3,000psi when the temperature is 15.0°C? PV=nRT R= 0.0821 Latm molk latm = 14.7psi O 15.2mol O42.0mol Ⓒ104mol 00.00966mol Ś olo Ar How many moles of oxygen gas are contained In a diver's tank of volume 12.0L and pressure 3,000psi when the temperature(s15.0c? PV-nRT 0.0821Latm R molK 1atm-14.7psi O15.2mol X 5 O42.0mol 104mol O0.00966mol