How many moles of water are produced by the complete combustion of 14.4 g of C5H12? C5H12 + 8O2 -> 5CO2 + 6H2O
Added by Lu-S K.
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01) + 12(1.008) = 72.15 g/mol. Moles C5H12 = 14.4 g / 72.15 gĀ·molā»Ā¹ = 0.1996 mol ā 0.200 mol. Show moreā¦
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