00:01
Okay, so we get the products with pharma reactions with orthometa and para xylene.
00:06
And xylene is just two method groups attached to a benzene ring, and chlorination is using chlorine gas and an acid catalyst, like alcl3.
00:15
And this is needed because the benzene ring is very stable, and it's not going to attack the chlorine directly.
00:21
The stability is inversely proportional to reactivity, meaning the more stable is the less reactive, which is why we need that acid catalyst.
00:40
So the cl2 and alcl3.
00:43
And ortho, meaning that one group is one carbon away from the other.
00:49
And the ortho position is also...
00:52
So the methyl groups are weekly activating.
00:57
They're electron dony groups.
00:59
And they're also orthopar directors.
01:01
So the orthoposition, again, is one carbon away from each group from this one.
01:06
If you put this one in red, it's going to be right there.
01:10
And then pair to the one in red would be 1, 2, 3, 4 here.
01:15
Pair to the one in black, b1, 2, 3, 4.
01:19
So we have all those positions.
01:21
We have to determine which ones are in duplicates of the others.
01:32
And first putting this group right there, and also the pair position, which is going to be right there, to the one in black.
01:48
Then for the one in red, it's going to be right here.
01:59
And also pair to that, be right here.
02:08
So we do have four products.
02:09
We have determined which ones are actually, are duplicates of the other.
02:15
So the chlorine, the c and chloro comes before the ammethyl.
02:19
And therefore, it's going to be, well, if we just call the xylene instead of the name for the methyls, this would be on carbon 3.
02:28
We went the lowest amount of numbers as possible.
02:32
So we're going to count from clockwise instead of counterclockwise, because that would give us higher numbers.
02:38
So that one's fine.
02:39
And then if we count this way, this is carbon 4, which is fine too.
02:44
But this actually would also be 3 chloro orthozyline, which you already have.
02:48
So we'd get rid of that.
02:50
And this would also be 4 chloro orthozyline if we count clockwise.
02:57
And we already have that one.
02:58
So in reality, you actually only have two products.
03:02
Next one is meta.
03:04
So just moving the one methyl group, one carbon away.
03:08
Right there.
03:22
So the orthoposition to both groups is right there.
03:26
And to this one, it's going to be right there...