00:01
Hello students, let's understand this problem in which two isotopes are given.
00:05
First one is the silicon 30 and second one is the phosphorus 32 and some questions are related to them are given.
00:14
In the first part we have to find out the number of electrons that are present in the silicon 30.
00:24
Now, atomic number of silicon is equal to the 14 and number of protons is equal to the atomic number.
00:40
And also number of protons is equal to the number of electrons.
00:49
So from here the number of electrons present in the silicon is the number of electrons present in silicon is 14.
01:03
Now in the next part we have to find out the number of neutrons that are present in the phosphorus 32.
01:16
Now, mass number is given, mass number of phosphorus is equal to 32 and number of protons are equal to the atomic number which is equals to 15.
01:30
Now there is a one formula that is a relation between a mass number proton and neutron.
01:36
That is mass number is equals to number of protons plus plus number of.
01:46
Neutrons.
01:48
So by substituting these value, we get the number of neutrons.
01:52
So mass number is 32 protons are 15 plus number of neutrons.
02:00
So from here, 32 minus 15 gives us the number of neutrons.
02:10
So the number of neutrons are 32 minus 15 give us the number of neutrons.
02:18
So the number of neutrons in phosphorus 32 is 17, which is option e.
02:32
Whereas in the first part, 14, answer we get answer is 14, which is option a.
02:39
Now, in the third part, we have to find out the number of protons, number of protons, number of protons.
02:50
In phosphorus 32...
