How many seconds are required to deposit 0.109 grams of tin metal from a solution that contains Sn2+ ions, if a current of 0.692 A is applied. s
Added by Marie S.
Step 1
First, we need to determine the number of moles of Sn2+ ions that are required to deposit 0.109 grams of tin metal. molar mass of Sn = 118.71 g/mol 0.109 g Sn x (1 mol Sn/118.71 g Sn) = 0.000919 mol Sn Show more…
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