00:01
So here we are asked to find the number of three digit number which can be formed from the digits 2, 4, 6 and 8, 2, 4, 6 and 8 given the following condition.
00:14
First one, the repetitions are not allowed.
00:18
Repetations are not allowed, which implies 4c1 which is equal to 4.
00:25
The next one is since the repetitions are not allowed and one digit is already used, then we have it in terms of 3c1 which is equal to 3, the number of ways of forming the second digits.
00:44
Now that we have used two digits, we have two more digits to be followed, that is 2c1, which is nothing but 2.
00:55
Two number of ways of forming the third digit.
00:58
This is first digit...