00:01
There is a solution of ch3 cooh, that is acidic acid plus ch3 c ona.
00:10
Now it is 0 .0185 molar and this is 0 .0240 molar.
00:19
P -ka for the reaction is also given, that is 4 .75.
00:24
Now in this volume, n -a -o -h is added.
00:30
Added and it is 5 .90 molar volume unknown.
00:37
Volume is un so here what we will do let us consider it to be xml now n a oh h n a o h it will break as n a plus plus o h minus and c h 3 c oho will break as c h plus h plus.
01:02
Now this o h minus will react now this n -a plus will react with ch3 c -o -o -o -minus c -o -na.
01:11
From here the initial concentration is 0 .0185 and o -h -minus concentration, n -a plus concentration is 5 .90.
01:20
So it will be 0 .0240 into 610.
01:26
It will come out to be 6 .10...