How much cobalt metal in grams can be produced running a 12.6-ampere current through Co(NO$_3$)$_2$ (aq) for 7.76 hours?
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Given: Current (I) = 12.6 amperes Time (t) = 7.76 hours Convert time to seconds: 7.76 hours * 3600 seconds/hour = 27,936 seconds Calculate the total charge passed through the solution using the formula: Q = I * t Q = 12.6 A * 27,936 s Q = 352,185.6 coulombs Show more…
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