Question

How much energy is necessary to place three +5.0-µC point charges at the vertices of an equilateral triangle of side 1.0 cm if they started out really far away? The electric potential is assumed to be zero really far away from the triangle. (k = 9.0 × 10? N ? m²/C²) 22.5 J 33.75 J 0.0 J 67.5 J

          How much energy is necessary to place three +5.0-µC point charges at the vertices of an equilateral triangle of side 1.0 cm if they started out really far away? The electric potential is assumed to be zero really far away from the triangle. (k = 9.0 × 10? N ? m²/C²)

22.5 J
33.75 J
0.0 J
67.5 J

How much energy is necessary to place three +5.0-µC point charges at the vertices of an equilateral triangle of side 1.0 cm if they started out really far away? The electric potential is assumed to be zero really far away from the triangle. (k = 9.0 × 10? N ? m²/C²)

22.5 J
33.75 J
0.0 J
67.5 J

Added by Samantha C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Nishant Kumar

02/10/2022

Step 1

Given: Charge (Q) = +5.0 μC = 5 x 10^-6 C Side length of the equilateral triangle (r) = 1.0 cm = 0.01 m k = 9.0 x 10^9 N·m^2/C^2 The potential energy for each pair of charges is given by: U = k * (Q1 * Q2) / r Since all charges are the same and equidistant, the Show more…

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How much energy is necessary to place three +5.0 ΑΑΑΑΑC point charges at the vertices of an equilateral triangle of side 1.0 cm if they started out really far away? The electric potential is assumed to be zero really far away from the triangle. (k = 9.0 x 10^9 N·m^2/C^2) 22.5 J 33.75 J 0.0 J 67.5 J