00:02
Here in this problem, mass of sample of iron given 222 gram, initial temperature is given 28 .3 degrees centigrade and the sample absorbs 2 .60 kilojoule heat energy.
00:17
And specific heat capacity of iron is 0 .449 jule per gram degree centigrade.
00:25
Now we have to find out the final temperature.
00:29
Let the final temperature be, let the final temperature be, let the final temperature be, uh, t degree centigrade.
00:41
Therefore, delta t, that is the difference in temperature will be t minus the final temperature minus the initial temperature, which is 28 .3.
00:55
Now, let's use the formula q is equal to m, c, delta, t.
01:04
Q is the heat energy absorbed or released.
01:07
M is the mass of the sample.
01:11
And c is the specific heat capacity and delta t is the difference in temperature.
01:16
Here, q given 2 .60 kilojoules.
01:20
So let's convert it into jule.
01:22
So we will multiply by 1 ,000, that is 10 cube...