10) How much energy is required to vaporize 41.4 g of dichloromethane (CH2Cl2) at its boiling point, if its ?Hvap is 31.6 kJ/mol? A) 18.1 kJ B) 15.4 kJ C) 31.2 kJ D) 6.49 kJ E) 55.1 kJ
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The molar mass of dichloromethane is 12.01 g/mol (for carbon) + 2*1.01 g/mol (for hydrogen) + 2*35.45 g/mol (for chlorine) = 84.93 g/mol. So, 41.4 g of dichloromethane is 41.4 g / 84.93 g/mol = 0.487 mol. Show more…
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