How much heat energy is released when 5.0 g of water at 20oC changes into ice at 0oC? Take specific heat capacity of water =4.2 J g-1 K-1, specific latent heat of fusion of ice =336 J g-1.
Added by Chris L.
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The formula to calculate the heat energy (\( Q \)) is: \[ Q = mc\Delta T \] where: - \( m \) is the mass of the water (5.0 g), - \( c \) is the specific heat capacity of water (4.2 J g\(^{-1}\) K\(^{-1}\)), - \( \Delta T \) is the change in temperature (20°C - Show more…
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